variable probleme steph 12/30/2008 3:54:06 AM Hi I would like to do this : $list="get-command","get-service" foreach ($l in $list) { echo $l foreach($i in $l) { $a=$i.name echo $a } } The probleme is : The variable in the second foreach ($ l) appears to be seen as a string and not a command.do anyone have an idea ? Thanks

Re: variable probleme "Vadims Podans" <vpodans> 12/30/2008 7:00:02 AM your $list contains strings, not commands. What you want to get? "steph" <steph[ at ]discussions.microsoft.com> rakstīja ziņojumā "news:1C916815-6FC5-4B0F-A39C-24CA307A0BE8[ at ]microsoft.com"... [Quoted Text] > Hi > > I would like to do this : > > $list="get-command","get-service" > foreach ($l in $list) > { > echo $l > foreach($i in $l) > { > $a=$i.name > echo $a > } > } > The probleme is : > The variable in the second foreach ($ l) appears to be seen as a string > and > not a command.do anyone have an idea ? > Thanks

Re: variable probleme "Kiron" <Kiron[ at ]HighPlainsDrifter.com> 12/30/2008 7:25:07 AM To execute the Cmdlet in the second Foreach use the Call operator '&'. You can also use Invoke-Expression or a dot. # call operator foreach($i in & $l) # invoke-expression's alias foreach($i in iex $l) # a dot foreach($i in . $l) -- Kiron

Re: variable probleme steph 12/30/2008 11:58:01 AM thanks to all "Kiron" wrote: [Quoted Text] > To execute the Cmdlet in the second Foreach use the Call operator '&'. > You can also use Invoke-Expression or a dot. > > # call operator > foreach($i in & $l) > > # invoke-expression's alias > foreach($i in iex $l) > > # a dot > foreach($i in . $l) > > -- > Kiron >